Question

A constant force acts on an object of mass 5kg for 2s. It increases objects velocity from 3m/s to 7m/s. calculate applied force. now if the force applied for duration of 5s , what would be the final velocity of the object.
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Answer 1

Answer:

f=m*a. so a= 7-3/2=2.

Explanation:

here acceleration=2 so we can find the force that is 5*2=10 so f= 10.