Question

A constant force acts on an object of mass 5kg for a period of 2seconds. It increases the object's velocity from 3m/s to 7m/s . Find the magnitude of the applied force. Now if the force applied for a period of 4 seconds, what would be the final velocity of the object?

Answer 1

Answer:

force=10N and v=11

Explanation:

v=u+at

7-3=a×2

a=2

f=5×2

v=3+2×4=11