Physics, asked by Umang7692, 1 year ago

A constant force acts on an object of mass 5kg for duration of 2s. It increases the objects velocity from 3m/s to 7 m/s. Find the magnitude of the applied force. Now, if the force was applied for a duration of 5sec.What would Be the final velocity of the object.

Answers

Answered by dikshitguptaji84
2

v=u+at

7=3+a 2

a=2 m/s^2

f=ma

f=5 .2=10

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