Question

A constant force acts on an object of mass 6 kg for a duration of 4s. It increases the
object's velocity from 4 m/s to 12 m/s. Find the magnitude of applied force.​

Answer 1

F = ma

F = m (v-u/t)

F= 6( 12-4/4)

F= 6 ( 8/4)

F= 6 × 2

F = 12 N

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Answer 2

Answer:

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