Physics, asked by rk0648970gmailcom, 7 months ago

a constant force acts on an object of mass 6 kg for a duration of 4 second it increases the objects velocity from 4 metre per second to 12 metre per second find the magnitude of applied force.​

Answers

Answered by janu5328r
0

answer:12newton

explanation:

given;

mass(m)=6kg

time(t)=4s

initial velocity (u)= 4ms–¹

final velocity (v)=12ms–¹

therefore, acceleration (a)=v-u/t

by substituting,12-4/4

so, accelaratin(a)=2m/s–²

now to find the force(f);

F=ma

f=6×2

hence, F=12N

OR

F=12kgms–²

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