a constant force acts on an object of mass 6 kg for a duration of 4 second it increases the objects velocity from 4 metre per second to 12 metre per second find the magnitude of applied force.
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answer:12newton
explanation:
given;
mass(m)=6kg
time(t)=4s
initial velocity (u)= 4ms–¹
final velocity (v)=12ms–¹
therefore, acceleration (a)=v-u/t
by substituting,12-4/4
so, accelaratin(a)=2m/s–²
now to find the force(f);
F=ma
f=6×2
hence, F=12N
OR
F=12kgms–²
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