A constant force acts on an object of mass 8 kg for the duration of 5 sec. it increases the velocity from 3m/s to 7m/s. find the magnitude of the applied force
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u=3 m/s
v= 7 m/s
t= 5 sec
a=( 7-3) /5 = 4/5 m/sec*sec
Force = mass *acceleration = 8 * 4/5 = 6.4 N
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v= 7 m/s
t= 5 sec
a=( 7-3) /5 = 4/5 m/sec*sec
Force = mass *acceleration = 8 * 4/5 = 6.4 N
Thank u friend
Pls mark as Brainliest
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