Question

a constant force acts on an object of mass 8kg for a duration of 4s .it increases from 5m/s to 10/ms .find the magnitude of applied force

Answer 1

Given :-

• Initial Velocity, u = 5 m/s
• Final Velocity, v = 10 m/s
• Time, t = 4 s
• Mass, m = 8 kg

To find :-

• Magnitude of applied force?

Solution :-

We know that,

★ Acceleration = (final velocity - initial velocity)/time

➻ a = (v - u)/t

➻ a = (10 - 5)/4

➻ a = 5/4

➻ a = 1.25 m/s²

━━━━━━━━━━━━━━━━━━━━━━━━━

Now, Finding force applied on object,

We know that,

★ Force = Mass × Acceleration

➻ F = m × a

➻ F = 8 × 1.25

➻ F = 10 N

∴ Hence, 10 N constant force is applied on an object.

Answer 2

$\large {\underline\mathfrak\red{Given:-}}$

• Initial velocity (u) = 5 m/s

• Final velocity (v) = 10 m/s

• Time (t) = 4 secs

• Mass (m) = 8 kg

$\large{ \underline {\frak \red{To ~Find:-}}}$

• The force applied on the object (f)

$\large{ \underline{ \frak \red{Solution:-}}}$

• We first need to find the acceleration of the object using the given formula :—

$\LARGE \boxed{ \boxed {\sf{Acceleration=\bf{ \dfrac{v-u}{t} }}}}$

$: \implies \frak{acceleration = \dfrac{5 + 10}{4} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: : \implies \frak{acceleration = \dfrac{50}{4} }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies {\underline{\boxed{\frak \pink{acceleration = 12.5 \: {m/s}^{2} }}}}$

____________________________

• Now we can find the force applied on the object by the given formula :—

$\LARGE \boxed{ \boxed {\sf{Force = \bf{Acceleration×Mass} }}}$

$: \implies \frak{force = 8 \times 12.5 }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: : \implies {\underline{ \boxed{ \frak \pink{force = 100 \: N}}}}$

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$\large {\underline\mathfrak\red{Answer:-}}$

• The force applied on the object = 100 N