Science, asked by ayshudahuda, 4 months ago

A constant force acts on an object of mass 8kg for a duration of 4 sec. It
increases the object's velocity from 12ms-1 to 48 ms-1 . Find the magnitude of
applied force.

Answers

Answered by inception2005

0

Answer:

72N

Explanation:

f=ma

f=m•v-u/t

8*48-12/4

f=72N

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