A constant force acts on the body of mass m at rest. The velocity v acquired in covering specific distance depends on m as-
Options_
1. V∝m
2. V∝1/m
3. V∝root of m
4. V∝1/root of m
Answers
Answered by
19
_____________________________________________________________
♦ Newtonian Mechanics ♦
→ Force imposed is • Constant •
→ Newton's Second Law : The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
_____________________________________________________________
◘ F = ma
=> F = m ( dv / dt )
=> ( F / m ) = ( dv / dt )
=> v ∝ ( 1 / m )
____________________________________________________________
◘ Momentum is the impetus gained by a moving object and is defined as :
• p = mv
◙ Force is the rate of change of momentum :-
• F = ( dp / dt ) => F ∝ p
=> F ∝ mv
=> v ∝ m⁻¹ [ Since 'F' is constant ]
_____________________________________________________________
► Above are two general proofs for the above .
→ A common confusion is :
• https://www.physicsforums.com/threads/313861/
_____________________________________________________________
→ Hope that helps
♦ Newtonian Mechanics ♦
→ Force imposed is • Constant •
→ Newton's Second Law : The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
_____________________________________________________________
◘ F = ma
=> F = m ( dv / dt )
=> ( F / m ) = ( dv / dt )
=> v ∝ ( 1 / m )
____________________________________________________________
◘ Momentum is the impetus gained by a moving object and is defined as :
• p = mv
◙ Force is the rate of change of momentum :-
• F = ( dp / dt ) => F ∝ p
=> F ∝ mv
=> v ∝ m⁻¹ [ Since 'F' is constant ]
_____________________________________________________________
► Above are two general proofs for the above .
→ A common confusion is :
• https://www.physicsforums.com/threads/313861/
_____________________________________________________________
→ Hope that helps
Similar questions