Question

A constant force acts on the object of mass 5 kg for 2 seconds. It increases the object's velocity from 3 m/s to 7 m/s.

Q(A) What is the initial momentum of the object.​

Answer 1

Explanation:

Let the Force be F

Mass is M

time for which it is accelerated =2s

velocity is increased from 3m/s to 7m/s

so, acceleration is ,a=(7-3)/2= 2m/s

the force applied is ,F= ma =(5)(2)=10N

Now the force is applied for 5s,the velocity after 5s willbe ,

v=u+at

v=3+(2)(5)

v=13m/s,this is the final velocity