Question

a constant force acts on the object of mass 5 kg for 2 seconds it increases the object velocity 3 metre per second to 7 metre per second now if the same force I was applied for a duration of 5 seconds what would be the final velocity of the object​

Answer 1

Step-by-step explanation:

ANSWER

Given,

mass=5kg

t1 =2s

Initial velocity u=3m/s

Final velocity v=7m/s

t 2 =5s

So,Let the Force be F ,Let the acceleration be a

So,

a= t(v−u) = 2(7−3 ) =2m/s 2

So the magnitude of the applied force is 10N

And the final velocity after 5s is v