Question

A constant force applied on an object of mass 2kg for 10s, increases its velocity from 5m/s to 10m/s . Find the magnitude of applied force. If the same force is applied for 15s, what will be the final velocity of object.

Answer 1

Step-by-step explanation:

Here initial velocity is 5m/s

and the final velocity is 10 m/s

given time is 10s

then acceleration = (10-5)/10

= 0.5 m/s2

then F = 2×0.5

= 1N

Answer 2

$\bold{Given :-}$

$\bold{mass \: = \: 10kg}$

$\bold{time \: = \: 1sec}$

$\bold{initial \: velocity \: (u) = 5m/s}$

$\bold{final \: velocity (v) \: = 10m/s}$

$\bold \red{acceleration \: = \frac{v - u}{t}}$

$\bold{a \: = \: \frac{10 - 5}{1} }$

$\bold{a \: = \: 5m/s²}$

$\bold \red{force \: = \: m \times a}$

$\bold{force \: = \: 10kg \: \times 5m/s²}$

$\bold \green{force \: = 50N.... \: \: \: ans}$