Physics, asked by Anonymous, 5 months ago

A constant force F= 3i + cj +6k acting on a particle causes a displacement s= -4i +2j +3k in its own direction. If the work done is 6 J, then value of ‘c’ is

a)0
b)1
c)6
d)12

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Answers

Answered by Atαrαh
18

Given :-

\bigstar \overrightarrow{F} = 3 \hat{i} + c \hat{j} + 6 \hat{k}

\bigstar\overrightarrow{s} = -4 \hat{i} + 2 \hat{j} + 3 \hat{k}

Work done = 6 J

To find :-

  • The value of c

Solution :-

The work done by an object is a scalar product of force and displacement .

Hence ,

\dag \boxed{ \pink{W = \overrightarrow{F}.\overrightarrow{s }}} \\ \\ \\

Now let's substitute the values in the above equation ,

\leadsto W = (3 \hat{i} + c \hat{j} + 6 \hat{k} ) .( -4 \hat{i} + 2 \hat{j} + 3 \hat{k}) \\ \\ \\ \leadsto W = - 12 + 2c + 18 \\ \\ \\ \leadsto W = 6 + 2c \\ \\ \\ \leadsto6 - 6 = 2c \\ \\ \\ \leadsto \boxed{ \red{c = 0 }}

The value of c is 0

Answered by Anonymous
8

Refer the attachment............

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