a constant force F = 3i+j–k N has a displacement r=2i+2j–3k meter in 2 seconds then calculate the power.
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•To find : power
• Given : constant ,F = 3i+j–k and
r=2i+2j–3k , time = 2 seconds
we know that ,
work done = Force . Displacement
= ( 3i+j–k ).(2i+2j–3k )
= (6+2+3)J
=11J
∴power = work done /time
=11/2 W
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