Question

a constant force F=(6.0i+4j) N acts on a particle and it undergoes a displacement S=(2i+6j) m. calculate the work done by the force​

Answer 1

Answer:

36 J

Explanation:

Work Done = $\vec{F}$ . $\vec{s}$

WD = (6i + 4j) . (2i + 6j)

WD = 6*2 +4*6

WD = 12 +24

WD = 36 Nm