Question

A constant force F acting on a body of mass 20 kg, changes its velocity from (2î), ms-1 to (6 i) -1 in 40s. Find the magnitude and direction of the force.​

Answer 1

Answer:

M = 20 kg

iv=2 m\s

fv=6m\s

a=6-2÷40=0.1 ms-2

F =ma=20×0.1=2N

Answer 2

The magnitude of force is 2 N and it is acting in x direction.

Explanation:

Given that,

Mass of the object, m = 20 kg

Initial speed of the body, $u=(2i)\ m/s$

Final speed of the body, $v=(6i)\ m/s$

Time, t = 40 s

We need to find the magnitude and the direction of force. Force is given by :

F = ma

$F=\dfrac{m(v-u)}{t}$

$F=\dfrac{20(6i-2i)}{40}$

$F=\dfrac{20\times (4i)}{40}$

$F=(2i)\ N$

Magnitude of force, $F=\sqrt{2^2}=2\ N$

So, the magnitude of force is 2 N and it is acting in x direction.

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