A constant force F acts separately on three objects having different masses such that the acceleration produced in the objects is in the ratio 1:2:3. Find the ratio of the masses. Also show your calculations.
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The ratio of their masses will be 6 : 3 : 2
Explanation :
from the law of motion, we know that,
F = ma
=> a = F/m
Let the three objects have acceleration of a₁, a₂, a₃ and there masses be m₁, m₂, m₃
it is given that,
a₁:a₂:a₃ = 1:2:3
=> F/m₁ : F/m₂ : F/m₃ = 1:2:3
=> 1/m₁ : 1/m₂ : 1/m₃ = 1:2:3
=>m₁ : m₂ : m₃ = 1 : 1/2 : 1/3 = 6 : 3 : 2
Hence the ratio of their masses will be 6 : 3 : 2
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