Physics, asked by galtise1rajesh, 2 months ago

A constant force F = m29/2 is applied
on the block of mass mį as shown in fig.
The
string and the pulley are light, and the
surface of the table is smooth. The
acceleration of mı is
m,
m2
O
m29
towards right
2(mi+m2)
m29
towards left
2(mı-m2)
m29
towards right
2(m2-mi)
m29
O
towards left
2(m2-m)​

Answers

Answered by tejas9193
0

Answer:

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