Question

A constant force F=m2g/2 is applied on the block of mass m1 as shown in the figure.the string and the pulley are light and the surface of the table is smooth.find the acceleration of m1.

Answer 1

total force= m2g (by m2 block) -m2g/2

=> m2g/2

as F= ma

m2g/2=(m1+m2)a

=>a=m2g/2(m1+m2)

Answer 2

Answer:

Refer to the attachment for your answer