Question

a constant force is applied fo 2 seconds on a body of mass 5 kg. as a result, if the velocity of the body is changed from 3m/s to 7m/s. find the value of applied force.​

Answer 1

Given :

• A constant force is applied fo 2 seconds on a body of mass 5 kg. as a result, if the velocity of the body is changed from 3m/s to 7m/s.

To Find :

• Force applied = ?

Solution :

• Time Interval = 2 seconds
• Mass of the body = 5 kg
• Initial velocity = 3 m/s
• Final velocity = 7 m/s

★ First of all we need to find the acceleration of the body by using first equation of motion :

• v = u + at

Where,

• v is the final velocity of the body.
• u is the initial velocity of the body.
• a is the acceleration of the body.
• t is the time taken by the body.

★ Plug in the given values in above equation of motion we get :

→ 7 = 3 + a × 2

→ 7 - 3 = 2a

→ 4 = 2a

→ a = 4 ÷ 2

→ a = 2 m/s²

• Hence,the acceleration of the body is 2 m/s².

★ Now, Let's calculate the force applied by the body :

→ Force = mass × acceleration

→ Force = 5 × 2

→ Force = 10 N

• Hence,the force applied by the body is 10 newton

Answer 2

$\huge{\boxed{\bold{Question}}}$a constant force is applied fo 2 seconds on a body of mass 5 kg. as a result, if the velocity of the body is changed from 3m/s to 7m/s. find the value of applied force.

Answer is attached