a constant force is applied for 2s on a body of mass 5kg.as a result,if the velocity of the body is changed from 3m/s to 7m/s find the value of the force applied
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Given :
- Intial velocity = 3 m/s.
- Final Velocity = 7 m/s.
- Mass of the body = 5 kg.
- Time = 2 s
To find :
Force applied by the body.
Solution :
First' let us find the Acceleration produced by the body .
We know the first Equation of Motion i.e,
⠀⠀⠀⠀⠀⠀⠀v = u + at
Where :
- v = Final Velocity
- u = Intial velocity
- a = Acceleration
- t = Time Taken
Using the first Equation of Motion and substituting the values in it, we get :
==> 7 = 3 + a(2)
==> 7 - 3 = 2a
==> 4 = 2a
==> 4/2 = a
==> 2 = a
∴ a = 2 m/s²
Hence the Acceleration produced by the body is 2 m/s².
Force applied :
We know the formula for force i.e,
⠀⠀⠀⠀⠀⠀⠀F = ma
Where :
- F = Force
- m = Mass
- a = Acceleration
Now by using the Equation for force and substituting the values in it, we get :
==> F = ma
==> F = 5 × 2
==> F = 10
∴ F = 10 N
Hence the force exerted by the body is 10 N.
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