Question

A constant force of 10newton acts on a body of mass 5kg at rest for 20sec and then ceases. Find the velocity and distance travelled by the body​

Answer 1

Answer:

refer 3 attachment above

Answer 2

Given

• Force = 10 N
• Mass = 5 kg
• Time = 20 sec

To Find

• The velocity and the distance covered by the body

Solution

● F = ma

● v = u + at

● v²-u² = 2as

✭ Acceleration of the body

→ F = ma

→ 10 = 5 × a

→ 10/5 = a

→ Acceleration = 2 m/s²

✭ Velocity of the body

→ v = 0 + 2 × 20

→ v = 0 + 40

→ v = 40 m/s

✭ Distance Covered

→ v²-u² = 2as

→ 40² - 0² = 2 × 2 × s

→ 1600 = 4s

→ 1600/4 = s

→ Distance = 400 m