Question

A constant force of 12 N is exerted for
seconds on a 24 kg object initially at rest. The
change in speed of this object will be
(a) 4 m/s
(b) 2 m/s
(c) 0.5 m/s
(d) 16 ms
A man weighing 70 kg carries a 30 kg box to​

Answer 1

Answer:

option (a) i guess

Answer 2

Answer:

sorry bro but the question is not complete because time is not given for which the force is applied on the body. If u have the value of time then......

Explanation:

force is given = 12N

mass of the body = 24 kg

so, acceleration of the body = F/m = 12/24 =

0.5m/s^2

now it is give it was at rest initially

so, by applying 1st eq. of motion

i.e., v = u + at

we get, v = at since u is 0

so now here put value of 't' you have and multiply it with 0.5 and you will get the answer

If you like it plzz vote for it