Question

A constant force of 12N acts ona body for 4 sec .find the change of linear momentum in the body.

Answer 1

As we know from Newton's second law of motion,

Rate of change of momentum=Force applied

P/t=F

P=Ft

P=12×4= 48 kgm/sec

Answer 2

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SOL:-

GIVEN :- FORCE (F) = 12N
∆T = 4 SEC.

WE KNOW THAT ,

F = ∆P/ ∆T

WHERE , P = MOMENTUM


∆P = F∆T

∆P = 12 × 4

∆P = 48 kgm/s

CHANGE IN LINEAR MOMENTUM IN THE BODY IS 48 kgm/s


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