Question

A constant force of 12N is applied for 3.0s to a body initially at rest. The final velocity of the body is 6.0ms–1. What is the mass of the body?

Answer 1

u=0
f=12N
t=3s
v=6m/s
v=u+at
6=0+a3
3a=6
acceleration=2m/s
force= mass. acc.
12=m.2
mass=6kg

Answer 2

$\boxed{ANSWER..}$

Constant force on a body = 12N

Initial velocity(u) = 0 (Because the body is at rest)

Final velocity(v) = 6m/s

Time = 3sec

Therefore ,

Acceleration = v - u / t

= 6 - 0 / 3

= 6/3

= 2m/s^2

We know that ,

Force = mass × acceleration

12N = mass × 2m/s^2

Mass = 12/2

Mass = 6Kg

$\bf{Therefore\: the\: mass\: of \:the \:body\: = \:6kg..}$