A constant force of 2.50 N accelerates a stationary particle of mass 15g through a displacement of 2.50m.find the work done and the average power delivered.
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Given conditions,
Force = 2.5 N,
Displacement = 2.5 m.
Work done = Force × displacement.
∴ Work done = 2.5 × 2.5
⇒ Work done = 6.25 J.
Now, Work-Energy Theorem,
Change in Kinetic Energy = Work done.
∴ 1/2 mv² = 6.25
⇒ v² = 6.25 × 2/(15 × 10⁻³)
∴ v² = 0.83333 × 10³
⇒ v = 28.8 m/s.
Using the Formula,
Power = Force × Velocity
∴ Power = 2.5 × 28.8
∴ Power = 72.17 W.
Hope it helps.
Answered by
4
Given ⇒
Force (F) = 2.5 N.
Mass of the Particle (m) = 15 g.
= 15/1000 kg.
= 0.015 kg.
Displacement covered by the particles(S) = 2.5 m.
For Calculating Work,
∵ Work Done = Force × Displacement
∴ W = F.S
⇒ W = 2.5 × 2.5
∴ Work Done = 6.25 J
Hence, the Work done by the Particles is 6.25 Joules.
For Power,
Work Done = 6.25 J.
Initial Velocity(u) = 0
[∵ Since, the Particles starts from the rest]
Using Newton's second law of Motion,
F = mass × acceleration.
⇒ Acceleration = Force/Mass
∴ a = 2.5/0.015
⇒ a = 500/3 (or 166.67) m/s².
Now, For Calculating the Final Velocity (v), Using the Formula,
v² - u² = 2aS.
⇒ v² - (0)² = 2(500/3)(2.5)
⇒ v² = 2500/3
⇒ v = √2500/3
∴ v = 50/√3 m/s.
Now, using the Formula for calculating time,
⇒ t = (50√3 - 0)/(500/3)
⇒ t = 50/√3 × 3/500
∴ t = 150/500√3 sec.
Now, Power = Work/Time.
⇒ P = 6.25/(150/500√3)
∴ P = 6.25 × 500√3/150
∴ P = 36.08 W.
Hence, Average Power Delivered by the Particle is 36.08 W.
Force (F) = 2.5 N.
Mass of the Particle (m) = 15 g.
= 15/1000 kg.
= 0.015 kg.
Displacement covered by the particles(S) = 2.5 m.
For Calculating Work,
∵ Work Done = Force × Displacement
∴ W = F.S
⇒ W = 2.5 × 2.5
∴ Work Done = 6.25 J
Hence, the Work done by the Particles is 6.25 Joules.
For Power,
Work Done = 6.25 J.
Initial Velocity(u) = 0
[∵ Since, the Particles starts from the rest]
Using Newton's second law of Motion,
F = mass × acceleration.
⇒ Acceleration = Force/Mass
∴ a = 2.5/0.015
⇒ a = 500/3 (or 166.67) m/s².
Now, For Calculating the Final Velocity (v), Using the Formula,
v² - u² = 2aS.
⇒ v² - (0)² = 2(500/3)(2.5)
⇒ v² = 2500/3
⇒ v = √2500/3
∴ v = 50/√3 m/s.
Now, using the Formula for calculating time,
⇒ t = (50√3 - 0)/(500/3)
⇒ t = 50/√3 × 3/500
∴ t = 150/500√3 sec.
Now, Power = Work/Time.
⇒ P = 6.25/(150/500√3)
∴ P = 6.25 × 500√3/150
∴ P = 36.08 W.
Hence, Average Power Delivered by the Particle is 36.08 W.
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