Question

a constant force of 200 newton is applied on a object for 4seconds to increase its speed from 3m/sto 11m/s on a straight path find the mass of the block​

Answer 1

Answer:

100kg

Explanation:

acceleration =v-u/t

=8/4=2m/s^2

F=ma

m=F/a

=200/2=100kg

Answer 2

Answer:

mass = 100 kg

Explanation:

We have , F = 200 N , t = 4 s

Acceleration = A = v - u / t , where v is final velocity and u is initial velocity

∴ A = 11-3 / 4 = 8/4 = 2 m/s

We know that , F = m . a

∴ Mass = m = F/a

∴ m = 200/2 = 100 kg