A constant force of 20N acts for 2s on a body of mass 2 kg initially at rest. how much distance will this body move in 3 s from start
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According to Newton's Second Law of Motion, “ The rate of change of momentum of a body is directly proportional to the applied force and takes place in the direction of the force.
By choosing one unit of force to be a force which produces an acceleration of one unit in a body of mass one unit, the constsnt of proportionality becomes 1, and the above law gives the equation,
F = ( m v - m u)/ t,
where, F = appled force, u = initial velocity, v= final velocity, t = time for which the force acts on the body of mass m, changing its momentum from m u to m v.
Accordingly,
m v - m u = change in momentum= F × t
In the present case force F = 100 N, and it acts on the body for 10 s, therefore
Change in momentum of the body= 100 N ×10 s= 1000 Ns.
By choosing one unit of force to be a force which produces an acceleration of one unit in a body of mass one unit, the constsnt of proportionality becomes 1, and the above law gives the equation,
F = ( m v - m u)/ t,
where, F = appled force, u = initial velocity, v= final velocity, t = time for which the force acts on the body of mass m, changing its momentum from m u to m v.
Accordingly,
m v - m u = change in momentum= F × t
In the present case force F = 100 N, and it acts on the body for 10 s, therefore
Change in momentum of the body= 100 N ×10 s= 1000 Ns.
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