A constant force of (2i+3j+4k)N produces a displacement of (3i+2j+3k) then the work done is
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Answered by
14
Work is dot product of work and displacement vectors
Work = Force · Displacement
= (2i + 3j + 4k) N · (3i + 2j + 3k)
= (6 + 6 + 12) Joule
= 24 Joule
∴ 24 Joule of work is done
Work = Force · Displacement
= (2i + 3j + 4k) N · (3i + 2j + 3k)
= (6 + 6 + 12) Joule
= 24 Joule
∴ 24 Joule of work is done
Answered by
5
work =force . distance
work= (2i+3j+4k). (3i + 2j + 3k)
work= 6+6+12
work= 24 unit
work= (2i+3j+4k). (3i + 2j + 3k)
work= 6+6+12
work= 24 unit
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