Question

A constant force of 400N acts on a body initially at rest , till thr velocity of the force act and the impulse .
Answer:
F=400N
u=0
v=32m/s
m=50kg
t=?
j=?
solution : F=m×a
a=400÷50 =8 m/s^2
v=u+at
32=0+8×t
t=32/8=4
therefore ; t=4 sec.​

Answer 1

Answer:

what is j can you tell me and if you asked question why have you solved that question

Answer 2

Answer:

jkNXaGiven, μ = 0, F = 100 dyn, t = 5 s and m = 25 g.

Now we know, F = ma.

∴ 100=25×a or, a = 4 cm⋅s−2

Therefore, v = u + at = 0 + 4 × 5 = 20 cm⋅s−1jzkmaGiven, μ = 0, F = 100 dyn, t = 5 s and m = 25 g.

Now we know, F = ma.

∴ 100=25×a or, a = 4 cm⋅s−2

Therefore, v = u + at = 0 + 4 × 5 = 20 cm⋅s−1HGiven, μ = 0, F = 100 dyn, t = 5 s and m = 25 g.

Now we know, F = ma.

∴ 100=25×a or, a = 4 cm⋅s−2

Therefore, v = u + at = 0 + 4 × 5 = 20 cm⋅s−1Given, μ = 0, F = 100 dyn, t = 5 s and m = 25 g.

Now we know, F = ma.

∴ 100=25×a or, a = 4 cm⋅s−2

Therefore, v = u + at = 0 + 4 × 5 = 20 cm⋅s−1Given, μ = 0, F = 100 dyn, t = 5 s and m = 25 g.

Now we know, F = ma.

∴ 100=25×a or, a = 4 cm⋅s−2

Therefore, v = u + at = 0 + 4 × 5 = 20 cm⋅s−1Given, μ = 0, F = 100 dyn, t = 5 s and m = 25 g.

Now we know, F = ma.

∴ 100=25×a or, a = 4 cm⋅s−2

Therefore, v = u + at = 0 + 4 × 5 = 20 cm⋅s−1

Explanation: