Question

A constant force of 50 N is applied on block of mass 5 kg which accelerates at a rate of 2 m/s2 on a rough horizontal surface. Then the frictional force acting between block and the surface is​

Answer 1

Answer:

The frictional force acting between block and the surface is​ 40 N

Explanation:

Given that,

          The applied Force, F = 50 N

          The mass of the block, m = 5kg

            Acceleration, a = 2 $m/s^{2}$

 F = ma - f    (where f is the frictional force)

 $50=\left(5\times 2\right)-f$

 $f=50-10=40N$