Question

a constant force of 50 newton is applied to an object of mass 10 kg moving initially with a velocity of 10 M per second how long will it take the object to stop if the force act on the object in a direction opposite to that of its velocity

Answer 1

The force exerts a deceleration on the body and it can be found by,

`F = ma`

`50 = 20 xx a`

`a = 2.5 ms^(-2)`

 

The deceleration is `2.5 ms^(-2).`

To find the time taken to stop the mass, we can use, v = u+at

 

`0 = 15 -2.5t`

`t = 15/2.5`

`t = 6 s.`

Answer 2

Answer:2 sec

Explanation:

F=ma

a=5m/s*2

V=u+at

t=2 sec