Question

a constant force of 50an applied to a body of mass 20 kg. what is its acceleration?
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Answer 1

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A.  Given that,

Force F=50N

Mass m=20kg

Initial velocity u=15m/s

Now, from newton’s second law

  F=ma

 50=20×a

 a=2.5m/s2

Now from equation of motion

  v=u+at

 0=15+(−2.5)t

 t=2.515

 t=6s

Hence, the body will be stop in 6 sec.

 B. Given that,

Mass of the body,m=3 kg

Initial speed of the body u=2 m/s

Final speed of the body v=3.5 m/s

Time, t=25 sec

Now, for acceleration

Use the equation of motion

  v=u+at

 a=t(v−u)

 a=253.5−2

 a=251.5

a=0.06 m/s2

Now, for the force

Use the newton’s second law

  F=ma

 F=3×0.06

 F=0.18 N

The magnitude of the force is 0.18 N.

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