Question

A constant force of 5N is applied continuously on a body of mass 10kg for 4s.The body moves 50cm along a straight line. What is the velocity of the body when the force applied intially?

Answer 1

Answer:

Explanation:

F = m×a

⇒  a = $\frac{F}{m}$

⇒a = $\frac{5}{10}$

⇒a = 0.5

Now using the formula $s = ut + \frac{1}{2} at^{2}$

⇒ 50= $u(4)+\frac{1}{2} (0.5)(4^{2} )$     ∵0.5  $= \frac{1}{2}$

⇒50 = $4u + \frac{1}{4} (16)$               ∵ $\frac{1}{2}$ × $\frac{1}{2}$ = $\frac{1}{4}$

⇒50 = $4u + 4$

⇒50-4 = $4u$

⇒ 46 = $4u$

⇒ $4u$ = 46

⇒ $u$ = $\frac{46}{4}$

⇒$u$ = 11.5 cm/s                  ∵ the units are in centimetres and seconds

which is also equal to 0.115 m/s

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