Question

A constant force of 75n acting on a body initial at rest gives it an acceleration of 0.3m/s for 10 sec.calculate the workdone by the force.

#Anwer. ​

Answer 1

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Mass of the body, m = 3 kg Initial speed of the body, u = 2 m/s Final speed of the body, v = 3.5 m/s Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

v=u+at

$a = \frac{(v - u)}{t}$

$a = \frac{3.5 -2 }{25}$

= 0.18 N

As per Newton's second law of motion, force is given as:

F = ma

= 3 x 0.06 = 0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

Answer 2

$\huge \color{lightgreen} \boxed {\color{pink}ANSWER}$

Mass of the body, m = 3 kg

Initial speed of the body, u = 2 m/s

Final speed of the body, v = 3.5 m/s

Time, t = 25 s

Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:

$v=u+at$

$a = \frac{v - u}{t}$

$= \frac{3.5 - 2}{25} = 0.06m/{s}^{2}$

As per Newton's second law of motion, force is given as:

F=ma

=3×0.06=0.18N

Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.