Question

A constant force of 8N acting on an object displaces it through a distance of 3.0 m in the direction of forcecalculate workdone by the force on the object.​

Answer 1

Answer:

• $Work\:done\:by\:the\:object=24\:J$

Explanation:

$Given:-$

• Force acting on object = 8 N
• Displacement of object = 3m

$ToFind:-$

• Work done by the object

$Solution :-$

$\implies \:\:Work \: done =fs \: cos \: \theta \\ \implies\:\: Work \: done =8 \times 3 \times cos \: 0 \degree \\ \implies\:\: Work \: done =24 \times 1 \\ \implies \:\:Work \: done =24 \: J$

$:)$

Answer 2

Answer:

Work Done = Force × Displacement

= 8×3

= 24 Nm or joule Answer

Explanation:

Hope it helps you