Question

A constant force of 9.0 KN, parallel to an inclined plane, moves a body of weight 20 KN through a distance of 40 m along the plane at constant speed. The body gains 12 m in height as shown. how much of the work done is dissipated as heat?​

Answer 1

Answer:

120 kj is the correct answer

Explanation:

The work done by the constant force of 9.0 kN to move the body a distance of 40 m is

Work done = 9.0 × 40 = 360 kJ

This energy is converted to the gravitational potential energy of the body. Some of the energy is also dissipated as heat.

Gain in gravitational potential energy of the body = 20 × 12 = 240 kJ

Work done = Gain in GPE + Heat dissipated

Heat dissipated = 360 – 240 = 120 kJ

Answer 2

Answer:

Heat dissipated = 320 - 240 = 120kj