A constant force of friction 50n is acting on a body of mass 200kg with a speed of 15m/s how long will the body take to stop
Answers
Answered by
4
F = mv/t
t = mv/F
= (200 * 15) / 50
= 60 seconds
= 1 minute
Time taken by body to stop is 1 minute.
t = mv/F
= (200 * 15) / 50
= 60 seconds
= 1 minute
Time taken by body to stop is 1 minute.
Answered by
5
f=mv/t
t=mv/f
50= 200×15/t
t= 200×15/50
t= 3000/50
t= 60 secs
Therefore,
Time taken to the object/body to stop is 1 minute(60secs)
Hope it helps you
t=mv/f
50= 200×15/t
t= 200×15/50
t= 3000/50
t= 60 secs
Therefore,
Time taken to the object/body to stop is 1 minute(60secs)
Hope it helps you
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