Question

A constant force of friction 50N is acting on a body of mass 200 Kg moving initially with a speed of 15 m/s. How long does the body take to stop? What distance will it cover before coming to rest?

Answer 1

Here. Refer to the attachment :)

Answer 2

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Retarding force,

F = –50 N

Mass of the body,

m = 200 kg

Initial velocity of the body,

u = 15 m/s

Final velocity of the body,

v = 0

Using Newton’s second law of motion, the acceleration (a) produced in the body can be calculated as:

F = ma

=> –50 = 200 × a

=> a= -50/200 = -0.25 m/s^2

Using the first equation of motion, the time (t) taken by the body to come to rest can be calculated as:

v = u + at

=> t= -u/a = -15/-0.25= 60 sec.

I hope, this will help you

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