A constant force of friction is acting on a body of mass 200 Kg moving with a speed 15 m/s.
How long does the body take to stop. What distance will it cover before coming to rest?
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Answer ❤
F=50 N
M=200 kg
V= 15m/s
F = MA
a = F/M = -50/200 = -0.25
Now using
V^2-U^2= 2as
0-(15)^2=2(-0.25)S
S=-225/-0.5=450m
As v= u+at
0=-15-0.25 t
t= -15/0.25
= 60 s
Hope its help u ❤
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