Question

A constant force of friction is acting on a body of mass 200 Kg moving with a speed 15 m/s.
How long does the body take to stop. What distance will it cover before coming to rest?

Answer 1

Answer ❤

F=50 N

M=200 kg

V= 15m/s

F = MA

a = F/M = -50/200 = -0.25

Now using

V^2-U^2= 2as

0-(15)^2=2(-0.25)S

S=-225/-0.5=450m

As v= u+at

0=-15-0.25 t

t= -15/0.25

= 60 s

Hope its help u ❤