Physics, asked by udayraj66618p9a7wg, 1 year ago

a constant force of friction of 50 Newton is acting on a body of mass 200 kg moving with velocity of 15 m/s . how does the body time take to stop ? and what distance cover before coming to rest?.

Answers

Answered by pranaykumar114

HEY MATE!!!

It will take 60 sec to stop the body
The distance covered will be 900m

Since the body is applying force on a direction is
200×15= 3000 N or
3000kgm/sec^2

Since sensor constant and opposite force of 50 Newton is applied on the body during the motion every second the force applied by the body is used by 50 Newton.

so dividing 3000 by 50 we get stopping time 60 seconds

NOW....
every single second the body is covering 15m. so after 60 seconds the body will cover
60×15 = 900 m

pranaykumar114: sorry bro....forgot the actual method.....done this by using some knowledge and logic....

pranaykumar114: I will remove it

pranaykumar114: report the answer if you want....i can't remove it now

udayraj66618p9a7wg: kasha logic hai bro. logic ans to change nshi karta hai.

zayn00: @udayraj66618p9a7wg Instead of finding mistakes you should rather tell that person it's not the right way rather than discouraging him/her.

pranaykumar114: Its not discouraging me....I just forgot the method and trying to remember it's so hard

pranaykumar114: done this type of question but can't remember the method

udayraj66618p9a7wg: nahi bro asa koi bat nahi hai aap na kosis kia bahut hai washa v aap ka time bilkul right aya hai . or mai aap ko discourse nahi kar raha hu please asa mat socho.

pranaykumar114: main nahin soch raha.....bas zara explain kar do ke distance 450m kyu hoga

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