Question

A constant friction force of 25 N acts on a 65-kg skier for 15 s on level snow. What is the skier’s change in velocity?

Answer 1

Answer:

so sorry I'm really bad on physics

Answer 2

Answer:

5.76 m/s

Explanation:

Given:

m= 65kg

f=25 N

t=15 s

Vi= 0 m/s

Formula:

FΔT=P

FΔT=mΔv

FΔT=m(Vf-Vi)

25(15)=65(Vf-0)

375 = 65(Vf)

Divide both sides by 65

375/65 = 5.76 m/s

Vf = 5.76 m/s