Question

A constant froce acts on object of mass 5kg for duration of 2 second it increases the object velocity form 3m/s to 7m/s.find the froce acted on the object​

Answer 1

Answer:

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Answer 2

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Given,mass=5kg

t

1

=2s

Initial velocity u=3m/s

Final velocity v=7m/s

t

2

=5s

So,

Let the Force be F

Let the acceleration be a

So,

a=

t

(v−u)

=

2

(7−3)

=2m/s

2

So the magnitude of the applied force is 10N

And the final velocity after 5s is v

So,

v=u+at

P

v=3+2×5

v=13m/s

The final velocity after 5s is 13m/s