Question

a constant immersion hydrometer floats vertically in water when the weight of its float is 30 g. When it is made to float in a liquid (miscible in water), the weight of its float is increased by 10 g. Find the weight of the hydrometer when it is floated in a mixture containing equal masses of water and the liquid.
can you please explain in detail

Answer 1

Answer:

34.28g

Explanation:

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Answer 2

The weight of the hydrometer is 35 g.

Explanation:

• The density of the liquid can find out by using the law of floatation.
• The density of mixture = density of liquid + density of water
• Now
• m - m(w) = 30 g ------(1)
• m - m1 = 30 + 10 = 40 g ------- (2)
• When hydrometer is immersed water displaced is m(w) / 2 and liquid displaced is m1 / 2.
• the weight of hydrometer:
• m - m() / 2 - m1 / 2
• Now add the equations.
• 2m - m(w) - m1 - 70  
• By dividing with 2 we get;
• m - m(2) / 2 - m1 / 2 = 35
• Thus the weight of the hydrometer is 35 g.