A constant power P is applied to a particle
of mass m. The distance travelled by the
particle when its velocity increases
101215 neglect friction)
(A) 32 (03 – va
(B) (02 – 01)
(C) (03- v)
(0)
m/..2
,2
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Time taken = 1 s Time taken to move first 5 m forward = 5 s Time taken to move 3 m backward = 3 s Net distance covered = 5 – 3 = 2 m Net time taken to cover 2 m = 8 s Drunkard covers 2 m in 8 s. Drunkard covered 4 m in 16 s. Drunkard covered 6 m in 24 s. Drunkard covered 8 m in 32 s. In the next 5 s, the drunkard will cover a distance of 5 m and a total distance of 13 m and falls into the pit. Net time taken by the drunkard to cover 13 m = 32 + 5 = 37 s Explanation:
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