A constant regarding force of 50N is applied to a body of mass 20kg moving initially with a speed of 15m per second . How long does the body take to stop?
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6
We know force = mass * acceleration
=>50N=20kg *a
=>a=(50/20) m/s2 = 2.5 m/s2 .........(1)
take acceleration (-2.5) as the speed of the body decreases to 0
here u=15m/s
v=0
according to the equation of motion
v=u+at
=>0=15-2.5*t
=>t=15/2.5
=6 s
=>50N=20kg *a
=>a=(50/20) m/s2 = 2.5 m/s2 .........(1)
take acceleration (-2.5) as the speed of the body decreases to 0
here u=15m/s
v=0
according to the equation of motion
v=u+at
=>0=15-2.5*t
=>t=15/2.5
=6 s
Answered by
2
We have force and mass so we can find acceleration
Also v=0 , u= 15 m/s
So, by applying eq of motion
v = u + at we can find "t"
Which will be 6s
Also v=0 , u= 15 m/s
So, by applying eq of motion
v = u + at we can find "t"
Which will be 6s
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