a constant rereading force 50 n is supplied to a body of 70 kg moving initially with the speed of 15 m/s .how long does the body take to stop
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Answer:
It will take 21.12 seconds for the body to take to stop.
Explanation:
Given,
A constant rereading force 50 N is supplied to a body of 70 kg moving initially with the speed of 15 m/s.
To find: how long does the body take to stop
Solution:
From Newton's second law,
Force = mass * acceleration
here, F = 50 N , m = 70 kg
On substituting the values,
50 = 70 * a
a = 50 / 70 = - 0.71 m/s² (as body is retarding)
Now, from first equation of motion,
v = u + at
here, v = 0 since the body is retarding. a = 0.71 m/s² and u = 15 m/s
Substituting the values,
0 = 15 + (-0.71)t
t = 15 / 0.71
t = 21.12 seconds
Therefore, It will take 21.12 seconds for the body to take to stop.
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