A constant retarding force of 10N is exerted to a body of mass 20kg moving initially with a speed of 10m/s. How long does the body take to stop?
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Answered by
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the answer is : 20 seconds
Answered by
1
Answer:
20 seconds
Explanation:
u = 10m/s
v = 0
m = 20kg
f = 10N
t = ?
Formula: F = ma
= m x (v - u / t)
10 = 20 x (0-10/t)
10 = 20 x (-10/t)
10 = -200/t
t = -200/10
t = -20 (as speed is retarding)
so, Time = 20 sec
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