Question

a constant retarding force of 20n acts on a body of mass 10 kg moving initially with a speed of 10m/s how long does the body take to stop

Answer 1

Answer:

5s

Step-by-step explanation:

Given,

• Force = -20N
• Mass = 10kg
• Speed = 10 m/s

a=$\frac{Force}{Mass}$

a = $\frac{-20}{10}$

a = -2 m/s²

v = u + at

Final Velocity(v) = 0 m/s

Initial Velocity(u) = 10 m/s

Acceleration(a) = -2 m/s²

0 m/s = 10 m/s +  (-2 m/s²)×t

t = $\frac{-10 m/s}{-2 m/s^{2}}$

t = 5s

Answer 2

Answer:

t = 5 sec

Step-by-step explanation:

F = -20N

M = 10 kg

u = 10 m/s

v = 0 m/s

t =?

F = m × a

-20 = 10 × a

a = -2m/s²

v = u + at

0 = 10 + (-2) × t

-10÷(-2) = t

t = 5 sec