a constant retarding force of 40N acts on a body of mass 5 kg moving initially E with a speed of 8 ms‐¹ how long does the body take to stop
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Answered by
2
Answer:
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4s
Explanation:
F = ma
-40 = 5 × a
a = -8 m/s²
and ,
v² = u² + 2as
u² = - 2as (v = 0)
8² = - 2 [-8] s
64 = 16 s
d = s = 64/16 = 4s
Answered by
0
Answer:
PLEASE MARK ME AS BRAINLIEST
Explanation:
F = ma
-40 = 5 × a
a = -8 m/s²
and ,
v² = u² + 2as
u² = - 2as (v = 0)
8² = - 2 [-8] s
64 = 16 s
d = s = 64/16 = 4s
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